For the three methods, the first argument is the String we. This program introduces the between, before and after methods. This matches at a certain position in the string, namely at a position right after the text sentence without making that text itself part of the match. To get what you're trying to do with lastSubstring(), you can efficiently use substring(). ![]() You can't efficiently find the last index with a given value using indexOf(), so lastIndexOf() is necessary. Input 'DEFINE:ATWO' Between ( 'DEFINE:', 'TWO') 'A'. I'm not aware of that sort of counterpart to substring(), but it's not really necessary. We have a text line that seems to define a variable between 2 parts. Run Javascript on the JVM with Rhino/Nashorn « With JavaScript’s function: var str = "abc?def,ghi?jkl,mno,pqr?stu,vwx?yz" Ĭonsole.log( parts ) // (5) Ĭonsole.log( str.split('?') ) // (5) Ĭonsole.log( parts ) // (3) Ĭonsole.log( str.split(/\?(. As we begin, it is important to understand the input and output of the Java program. My actual intention is to substring it from nth occurrence of a character. String split = decodeMainURL.split(Pattern.quote( "?" ), 2) In this case, if I ask for 3rd occurrence of slash (/), it appears before folder3, and I expect to return this index position. String decodeMainURL = code(myMainUrl, "UTF-8") Use a better overload like String.split (String regex, int limit). String wantedPart lineOfText.substring (lineOfText.indexOf (',') + 1) Since indexOf returns the index of the, itself, you need to add one to get everything past it. String myMainUrl = "" + subURL +"&name=chrome&version=56" Find the index (position) of the first, and substring using that index. String subURL = URLEncoder.encode( paramUrl, "UTF-8") I have face the same problem in URL parameters, To resoleve it i need to split based on first ? So that the remaing String contains parameter values and they need to be split based on &. String str '123dance456' String substr 'dance' String parts str.split(substr) String before parts0 String after parts1 It is noteworthy that the second answer not work if we have more than one occurrence of the substring. String split = str.split(quotedText, 2) // ![]() ? - \\? we have to escape sequence of some characters, to avoid use Pattern.quote( "?" ) ![]() indexOf (char): String substrmysourcestring.substring (mysourcestring. String quotedText = Pattern.quote( "?" ) Using String.substring() The easiest way is to use the built-in substring() method of the String class. If you want to get substring from specific character till end you can use : String substrmysourcestring.substring (mysourcestring.indexOf ('characterValue')) If you want to get substring from after a specific character, add that number to. String str = "abc?def,ghi?jkl,mno,pqr?stu,vwx?yz" The string "boo:and:foo", for example, yields the following results with these parameters: Regex Limit Result Using Java String.split(String regex, int limit) with Pattern.quote(String s) There are two types of substring methods in Java string. Three additional methods have been added: matches, replaceAll, and replaceFirst. The subSequence method has been added, as required by the CharSequence interface that String now implements. From jse1.4 String - Two split methods are new. There are 12 characters with special meanings: the backslash \, the caret ^, the dollar sign $, the period or dot. Note that split's argument is assumed to be a regular expression, so remember to escape special characters if necessary. Use the appropriately named method String#split().
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